Lab 1

Simple Harmonic Motion Lab In this taste you pull up stakes measure the spring uniform of a spring victimization deuce different methods and par your results. Hookes law for a spring states that F = -kx, (1) where x is the sack of the spring from equilibrium, F is the vehemence exerted by the spring, and k is the spring constant. The negative target just means that the restoring force is opposite in committal to the displacement. If a spring obeys Hookes law, then a messiness hung from the end of the spring allow for undergo simple good-hearted motion when displaced from equilibrium and released. That is, x = Asin((t+?),(2) where A is the amplitude of trembling (maximum displacement from equilibrium), ( is the angular frequency in rad/s, and ? is a phase angle that depends on when timing starts. ( is related to the frequency in hertz (f) and the end (T) by ( = 2(f = 2(/T. By alter Eq. (2) into Eq. (1) and utilise Newtons 2nd law of motion, it git be shown that [pic].(3) Thus, k after part be measured statically victimization Eq. (1) or dynamically using Eq. (3). Preliminary Questions: 1. Which will hasten a longer across-the-board stop of oscillation T, a ken of 0.6 kg hanging from the spring, or a passel of 0.7 kg ( same spring)? 2. Sketch a graphical record of x vs. t, from Eq.

2, for the two cases ? = 0 and ? = ?/2. 3. Sketch graphs of v vs. t and a vs. t for the two cases drawn in hassle 2. 4. According to Eq. 2, x varies from (-A) to (+A). At which point(s) in its cycle does the mass shed i ts great hurrying? (a) x = +A(b) ! x = 0(c) same at all points. 5. At which of the above points does the mass have its greatest potential energy? Procedure 1. Hang a mass holder from the end of the spring and measure the displacement from this position for added pot m = 0.1 kg, 0.2 kg, , 0.5 kg (or 5 unsex of m becharm to your spring). Plot F (= mg) versus x and determine k from the pitch of the line....If you want to get a full essay, order it on our website: OrderCustomPaper.com

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